The sum of the squares of two consecutive odd numbers is 130. Find the larger number.


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Question Number 137645 by mey3nipaba last updated on 05/Apr/21

$T h e s u m o f t h e s q u a r e s o f t w o c o n s e c u t i v e$ $o d d n u m b e r s i s 130 . F i n d t h e l a r g e r n u m b e r .$
	Answered by bemath last updated on 05/Apr/21
	$x^2 +(x+2)^2 =130 2x^2 +4x−126=0 x^2 +2x−63=0 (x+9)(x−7)=0 { ((x=7 )),((x+2=9 (the larger number))) :}$
	$x^{2} + {(x + 2)}^{2} = 130$ $2 x^{2} + 4 x - 126 = 0$ $x^{2} + 2 x - 63 = 0$ $(x + 9) (x - 7) = 0$ ${\begin{cases} x = 7 \\ x + 2 = 9 (t h e l a r g e r n u m b e r) \end{cases}$
	Commented by mey3nipaba last updated on 05/Apr/21

	$y e a h . t h a n k s s o m u c h$
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