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Question Number 137700 by peter frank last updated on 05/Apr/21

Commented by mr W last updated on 05/Apr/21

$${it}^{\prime }snottrue!$$$$example:$$$$b=c=-1,a=\frac{1}{\sqrt[3]{2}}$$$$\frac{1}{a^3}+\frac{1}{b^3}+\frac{1}{c^3}=0$$$$but{(a+b+c)}^3={(\frac{1}{\sqrt[3]{2}}-2)}^3\ne 27abc=\frac{27}{\sqrt[3]{2}}$$

Commented by peter frank last updated on 05/Apr/21

$$thankyousomuchforconfirmation$$

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