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Question Number 137907 by peter frank last updated on 08/Apr/21

	Answered by EnterUsername last updated on 08/Apr/21

	$\int_{1}^{e} \frac{1 + l n x}{x} d x = \int_{1}^{e} (\frac{1}{x} + \frac{l n x}{x}) d x$ $= {[l n x + \frac{{l n}^{2} x}{2}]}_{1}^{e} = 1 + \frac{1}{2} = \frac{3}{2}$ $(N o t i c e \frac{d l n x}{d x} = \frac{1}{x})$
	Commented by peter frank last updated on 08/Apr/21

	$t h a n k y o u$
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