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Question Number 138114 by mnjuly1970 last updated on 10/Apr/21
......calculus.....(III)......evaluate::ϕ=???∫0π2∫0xcos(y)(π2−x)(π2−y)dydx
Commented by Kamel last updated on 10/Apr/21
Commented by mnjuly1970 last updated on 10/Apr/21
thanksalotmr..kamel
Answered by mnjuly1970 last updated on 10/Apr/21
ϕ=∫0π2∫yπ2cos(y)(π2−x)(π2−y)dxdy=2∫0π2cos(y)π2−y[−π2−x]yπ2dy=2∫0π2cos(y)dy=2sin(π2)=2...✓
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