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Question Number 13886 by tawa tawa last updated on 24/May/17

Answered by ajfour last updated on 24/May/17

$$2.$$$$F=\frac{e^2}{4\pi {ϵ}_0{r}^2}$$$$r^2={(1.6\times {10}^{-19})}^2\left(9\times {10}^9\right)m^2$$$$r^2=2.56\times 9\times {10}^{-29}{m}^2$$$$r=1.6\times 3\times \sqrt{10}\times {10}^{-15}m$$$$=4.8\times 3.16\times {10}^{-15}m$$$$=15fm.$$$$$$$$3).$$$$F=\frac{{\left(Ne\right)}^2}{4\pi {ϵ}_0{d}^2}\Rightarrow N=\left(\frac{d}{e}\right)\sqrt{\left(4\pi {ϵ}_0\right)F}$$$$=\left(\frac{3\times {10}^{-2}}{1.6\times {10}^{-19}}\right)\sqrt{\frac{{10}^{-19}}{9\times {10}^9}}$$$$=\frac{5}{8}\times {10}^3=625.$$

Commented by tawa tawa last updated on 24/May/17

$$\mathrm{I}\mathrm{really}\mathrm{appreciate}\mathrm{your}\mathrm{effort}\mathrm{sir}.\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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