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Question Number 138879 by peter frank last updated on 19/Apr/21

Answered by Dwaipayan Shikari last updated on 19/Apr/21

$$e^{i\theta (1+2+3+4+..n)}=1\Rightarrow e^{i\theta \frac{n(n+1)}{2}}=e^{2\pi im}(m\in \mathbb{Z})$$$$\Rightarrow \theta =\frac{4\pi m}{n(n+1)}$$

Commented by peter frank last updated on 20/Apr/21

$$thankyou.$$

Commented by peter frank last updated on 20/Apr/21

$$howpartb$$

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