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Question Number 138998 by ZiYangLee last updated on 21/Apr/21

$$\int \left(\frac{e^{-1/x}}{x^2}\right)dx=?$$

Answered by phanphuoc last updated on 21/Apr/21

$$=\int e^{(-1/x)}d(-1/x)=e^{-1/x}+c$$

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