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Question Number 139108 by BHOOPENDRA last updated on 22/Apr/21

Answered by physicstutes last updated on 22/Apr/21

$$\lambda =0.1317{\mathrm{year}}^{-1},t=21.04\mathrm{years},N_0=1\mathrm{g}$$$$\mathrm{Using}\mathrm{the}\mathrm{decay}\mathrm{equation}:$$$$N=N_0{e}^{-\lambda t}$$$$=\left(1\right){\left(e\right)}^{(-0.1317)(21.04)}\mathrm{g}=0.006\mathrm{g}$$

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