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Question Number 139599 by I want to learn more last updated on 29/Apr/21

	Answered by mr W last updated on 29/Apr/21

	Commented by mr W last updated on 29/Apr/21

	$‘ ‘ a l l {f o r c e s}^{″} m e a n s i n c l u d i n g w e i g h t$ $o f b l o c k : F_{4} = m g = 10 N .$ $x c o m p o n e n t o f a l l f o r c e s :$ $F_{x} = 20 \times \frac{4}{5} + 10 \times \frac{3}{5} + 10 \times \frac{4}{5} + 10 \times 0 = 30 N (\to)$ $y c o m p o n e n t o f a l l f o r c e s :$ $F_{y} = 20 \times \frac{3}{5} + 10 \times \frac{4}{5} - 10 \times \frac{3}{5} - 10 \times 1 = 4 N (↑)$ $F = \sqrt{30^{2} + 4^{2}} = 2 \sqrt{229} N$ $m a = F$ $a = \frac{F}{m}$ $s = \frac{1}{2} {a t}^{2} = \frac{{F t}^{2}}{2 m}$ $w o r k d o n e b y a l l f o r c e s o n t h e b l o c k :$ $W = F s = \frac{F^{2} t^{2}}{2 m} = \frac{4 \times 229 \times 1^{2}}{2 \times 1} = 458 J$ $o r$ $W = E = \frac{1}{2} {m v}^{2} = \frac{1}{2} m {(a t)}^{2} = \frac{F^{2} t^{2}}{2 m}$
	Commented by I want to learn more last updated on 29/Apr/21

	$Thanks sir . I really appreciate . God bless you sir .$
	Commented by Dwaipayan Shikari last updated on 29/Apr/21

	$Σ F_{x} = 30 N$ $Σ F_{y} = 14 N$ $S_{x} = \frac{1}{2} . \frac{Σ F_{x}}{m} {(1)}^{2} = 15 m S_{y} = \frac{1}{2} . \frac{Σ F_{y} - m g}{m} {(1)}^{2} = 2 m$ $W o r k d o n e = S_{x} Σ F_{x} + S_{y} Σ F_{y} = 450 + 14 \times 2 J = 478 J$ $S o r r y s i r . I d e l e t e d m y p o s t d u e t o e r r o r s . B u t t h a t a l s o d e l e t e d$ $y o u r p o s t$
	Commented by I want to learn more last updated on 29/Apr/21

	$Thanks sir . God bless you . I really appreciate .$
	Commented by mr W last updated on 29/Apr/21

	$y o u a r e r i g h t s i r . j u s t o n e t h i n g :$ $t h e q u e s t i o n s a y s w o r k d o n e b y a l l$ $f o r c e s a c t i n g o n t h e b l o c k . i t s h o u l d$ $a l s o i n c l u d e t h e g r a v i t y f o r c e, w h i c h$ $d i d a w o r k i n y d i r e c t i o n : - 10 \times 2 = - 20 J .$
	Commented by Tawa11 last updated on 14/Sep/21

	$nice$
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