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Question Number 139642 by ajfour last updated on 30/Apr/21

If  0<c^2 <(4/(27))  , and  m{4c^2 −m(1+m)^2 }       ={m(1+m)^2 −3c^2 }^2   then  find real values of m in terms  of c^2 .

$${If}\:\:\mathrm{0}<{c}^{\mathrm{2}} <\frac{\mathrm{4}}{\mathrm{27}}\:\:,\:{and} \\ $$ $${m}\left\{\mathrm{4}{c}^{\mathrm{2}} −{m}\left(\mathrm{1}+{m}\right)^{\mathrm{2}} \right\} \\ $$ $$\:\:\:\:\:=\left\{{m}\left(\mathrm{1}+{m}\right)^{\mathrm{2}} −\mathrm{3}{c}^{\mathrm{2}} \right\}^{\mathrm{2}} \:\:{then} \\ $$ $${find}\:{real}\:{values}\:{of}\:{m}\:{in}\:{terms} \\ $$ $${of}\:{c}^{\mathrm{2}} . \\ $$

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