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Question Number 139654 by otchereabdullai@gmail.com last updated on 30/Apr/21

Commented by mr W last updated on 30/Apr/21

$$toolessinformationtofindx!$$$$youshouldgivee.g.ACorDC.$$

Commented by mr W last updated on 30/Apr/21

Commented by mr W last updated on 30/Apr/21

$$DC=\frac{h}{\tan \alpha }$$$$x+DC=\frac{h}{\tan \beta }$$$$\Rightarrow x=(\frac{1}{\tan \beta }-\frac{1}{\tan \alpha })h$$

Commented by mr W last updated on 30/Apr/21

Commented by mr W last updated on 30/Apr/21

$$AC=b\tan \alpha$$$$x+b=\frac{AC}{\tan \beta }=\frac{\tan \alpha }{\tan \beta }\times b$$$$\Rightarrow x=(\frac{\tan \alpha }{\tan \beta }-1)b$$

Commented by otchereabdullai@gmail.com last updated on 30/Apr/21

$$\mathrm{Wow}\mathrm{wow}\mathrm{wow}!\mathrm{nice}\mathrm{one}\mathrm{prof}\mathrm{thanks}$$

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