A rectangular blade ABCD is hanged up on A. If AB=2 m; AD=3m , the angle between (AD) and the verticale when the system is equilibred is: a)56.3 ° b)Arcsin(2/3) c)41.8° d)33.7°


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Question Number 139740 by mathocean1 last updated on 30/Apr/21

$A r e c t a n g u l a r b l a d e A B C D i s h a n g e d u p$ $o n A . I f A B = 2 m; A D = 3 m, t h e$ $a n g l e b e t w e e n (A D) a n d t h e$ $v e r t i c a l e w h e n t h e s y s t e m i s$ $e q u i l i b r e d i s :$ $a) 56.3 °$ $b) A r c s i n \frac{2}{3}$ $c) 41.8 °$ $d) 33.7 °$
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