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Question Number 139740 by mathocean1 last updated on 30/Apr/21

A rectangular blade ABCD is hanged up  on A. If AB=2 m; AD=3m , the  angle between (AD) and the   verticale when the system is   equilibred is:  a)56.3 °  b)Arcsin(2/3)  c)41.8°  d)33.7°

$${A}\:{rectangular}\:{blade}\:{ABCD}\:{is}\:{hanged}\:{up} \\ $$$${on}\:{A}.\:{If}\:{AB}=\mathrm{2}\:{m};\:{AD}=\mathrm{3}{m}\:,\:{the} \\ $$$${angle}\:{between}\:\left({AD}\right)\:{and}\:{the}\: \\ $$$${verticale}\:{when}\:{the}\:{system}\:{is}\: \\ $$$${equilibred}\:{is}: \\ $$$$\left.{a}\right)\mathrm{56}.\mathrm{3}\:° \\ $$$$\left.{b}\right){Arcsin}\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\left.{c}\right)\mathrm{41}.\mathrm{8}° \\ $$$$\left.{d}\right)\mathrm{33}.\mathrm{7}° \\ $$$$ \\ $$

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