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Question Number 139825 by mathdave last updated on 01/May/21

Commented by mr W last updated on 01/May/21

$r a t e o f c h a n g i n g o f d i s t a n c e i s t h e$ $s u m o f t h e s p e e d s o f t h e c a r s :$ $c a s e 1 :$ $- (50 + 40) = - 90 k m / h i f A w a s t o$ $t h e n o r t h o f B . t h e d i s t a n c e d e c r e a s e s .$ $c a s e 2 :$ $(50 + 40) = 90 k m / h i f A w a s t o$ $t h e s o u t h o f B . t h e d i s t a n c e i n c r e a s e s .$
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