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Question Number 139950 by I want to learn more last updated on 02/May/21

Answered by TheSupreme last updated on 02/May/21

$$y=y_0+6t-\frac{4}{2}{t}^2-v_{0,raptor}t$$$$y\left(0\right)=64$$$$y\left(4\right)=32$$$$64+6\times 4-2+4^2-v_{0}4=32$$$$64+24-32-v_{0}4=32$$$$v_{0}4=24$$$$v_0=6$$$$$$$$0=64+6t^{\ast }-2t^{\ast 2}-6t\ast =64-2t^{\ast 2}$$$$t^{\ast }=\sqrt{32}=4\sqrt{2}$$$$timeremaining=4(\sqrt{2}-1)$$$$$$$$\frac{dy}{dt}=-4t$$$$$$$$$$

Commented by I want to learn more last updated on 02/May/21

$$\mathrm{Thanks}\mathrm{sir},\mathrm{i}\mathrm{appreciate}.$$

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