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Question Number 140042 by denzel last updated on 03/May/21

Answered by MJS_new last updated on 03/May/21

$$254=\frac{1269}{4+{46\mathrm{e}}^{-.3t}}$$$$\mathrm{just}\mathrm{transform}\mathrm{it}$$$${\mathrm{e}}^{-.3t}=\frac{\frac{1269}{254}-4}{46}=\frac{11}{508}$$$$-.3t=\ln \frac{11}{508}$$$$t=\frac{\ln \frac{11}{508}}{-.3}\approx 12.78\Rightarrow \mathrm{given}\mathrm{answer}\mathrm{is}\mathrm{wrong}$$

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