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Question Number 140148 by aliibrahim1 last updated on 04/May/21

Answered by EDWIN88 last updated on 04/May/21

$$(\ast )\mathrm{vol}=\pi \underset{1}{\stackrel{4}{\int }}{\mathrm{x}}^2\mathrm{dy}=\pi {\left(\frac{1}{2}{\mathrm{y}}^2\right)}_1^4=\frac{15\pi }{2}$$$$(\ast \ast )\mathrm{vol}=2\pi \underset{1}{\stackrel{2}{\int }}\mathrm{x}.{\mathrm{x}}^2\mathrm{dx}=2\pi \underset{1}{\stackrel{2}{\int }}{\mathrm{x}}^3\mathrm{dx}=\frac{1}{2}\pi {\left({\mathrm{x}}^4\right)}_1^2$$$$\mathrm{vol}=\frac{15\pi }{2}$$

Commented by aliibrahim1 last updated on 04/May/21

$$thxsirappreciateit$$

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