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Question Number 140193 by mathdanisur last updated on 05/May/21
Solveforrealnumbers4sinπ26+4xsin3π26+4sin9π26=x+13
Answered by Dwaipayan Shikari last updated on 05/May/21
x(1−4sin3π26)=4(sin9π26+sinπ26)−13x=4(sin9π26+sinπ16)−13(1−4sin3π26)
Commented by mathdanisur last updated on 05/May/21
continuedSirpliz
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