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Question Number 140346 by mathsuji last updated on 06/May/21

$$if,x>4;5!\cdot x!=z!;find:x+z=?$$

Answered by hknkrc46 last updated on 06/May/21

$$5!=\frac{\mathit{z}!}{\mathit{x}!}\Rightarrow \{\begin{array}{l}\mathit{x}=5!-1\Rightarrow \mathit{z}=120\\ \mathit{x}+\mathit{z}=119+120=239\end{array}$$

Commented bymathsuji last updated on 07/May/21

$$thankyousircool$$

Answered by mr W last updated on 06/May/21

$$5!=120=4\times 5\times 6=2\times 3\times 4\times 5$$ $$x!\times 120=z!\Rightarrow x=119,z=120$$ $$x!\times 4\times 5\times 6=z!\Rightarrow x=3,z=6$$ $$x!\times 2\times 3\times 4\times 5=z!\Rightarrow x=1,z=5$$ $$forx>4thereisonlyonesolution:$$ $$x=119,z=120$$

Commented bymathsuji last updated on 07/May/21

$$thakyousircool$$

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