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Question Number 140497 by benjo_mathlover last updated on 08/May/21

sin^(−1) (sin x)=x  sin^(−1) (cos x)=?  sin^(−1) (tan x)=?

sin1(sinx)=xsin1(cosx)=?sin1(tanx)=?

Commented by mr W last updated on 08/May/21

sin^(−1) (sin x)=x is not always true.

sin1(sinx)=xisnotalwaystrue.

Commented by liberty last updated on 09/May/21

for what value of x this not true?

forwhatvalueofxthisnottrue?

Commented by mr W last updated on 09/May/21

example  sin^(−1) (sin ((5π)/4))=−(π/4)≠((5π)/4)

examplesin1(sin5π4)=π45π4

Commented by liberty last updated on 09/May/21

((5π)/4)∉D since not satisfy the equation

5π4Dsincenotsatisfytheequation

Commented by liberty last updated on 09/May/21

y=sin^(−1) (x) has domain −(π/2)≤x≤(π/2)

y=sin1(x)hasdomainπ2xπ2

Commented by mr W last updated on 09/May/21

y=sin^(−1) (x) has domain −1≤x≤1  y=sin^(−1) (x) has range −(π/2)≤x≤(π/2)    y=sin^(−1) (sin (x)) has domain −∞≤x≤∞  y=sin^(−1) (sin (x)) has range −(π/2)≤x≤(π/2)

y=sin1(x)hasdomain1x1y=sin1(x)hasrangeπ2xπ2y=sin1(sin(x))hasdomainxy=sin1(sin(x))hasrangeπ2xπ2

Commented by mr W last updated on 09/May/21

Answered by EDWIN88 last updated on 08/May/21

let sin^(−1) (cos x) = y   cos x = sin y ; sin ((π/2)−x)=sin y   we get y = (π/2)−x so sin^(−1) (cos x) = (π/2)−x

letsin1(cosx)=ycosx=siny;sin(π2x)=sinywegety=π2xsosin1(cosx)=π2x

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