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Question Number 140503 by ERA last updated on 08/May/21

$$\mathbf{P}\mathrm{rove}\mathrm{it}$$$$\sqrt{\mathit{a}+\sqrt{\mathit{b}}}=\sqrt{\frac{\mathit{a}+\sqrt{{\mathit{a}}^2+\mathit{b}}}{2}+}\sqrt{\frac{\mathit{a}-\sqrt{{\mathit{a}}^2-\mathit{b}}}{2}}$$

Commented by MJS_new last updated on 08/May/21

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{wrong}$$

Commented by MJS_new last updated on 10/May/21

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{still}\mathrm{wrong}$$

Commented by Dwaipayan Shikari last updated on 10/May/21

$$Itshouldbe\sqrt{\frac{a+\sqrt{a^2-b}}{2}}+\sqrt{\frac{a-\sqrt{a^2-b}}{2}}$$

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