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Question Number 140529 by SOMEDAVONG last updated on 09/May/21

Answered by Rasheed.Sindhi last updated on 09/May/21

(1/(x^2 (x+2)))−(5/((x−2)(x+2)))−(4/(x−2)) =((1(x−2)−5(x^2 )−4( x^2 (x+2) ))/(x^2 (x−2)(x+2))) =((x−2−5x^2 −4 x^3 −8x^2 )/(x^2 (x−2)(x+2))) =((−4x^3 −13x^2 +x−2 )/(x^2 (x−2)(x+2)))

1x2(x+2)−5(x−2)(x+2)−4x−2=1(x−2)−5(x2)−4(x2(x+2))x2(x−2)(x+2)=x−2−5x2−4x3−8x2x2(x−2)(x+2)=−4x3−13x2+x−2x2(x−2)(x+2)

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