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Question Number 140615 by bramlexs22 last updated on 10/May/21
Findtheareacommontothecurvey2=12xandx2+y2=24x.
Answered by EDWIN88 last updated on 10/May/21
Area=23.24.124+π2.14472=192+72π
Commented by EDWIN88 last updated on 10/May/21
Commented by Dwaipayan Shikari last updated on 10/May/21
∫01212xdx=2123(1212)=96(Halfpartinpositivehalf)x2−24x+y2=0⇒(x−12)2+y2=122Otherhalf=π4(12)2=36πTotalAreainenclosedintwohalves=2(96+36π)=192+72π
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