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Question Number 140688 by mohammad17 last updated on 11/May/21

Commented by mohammad17 last updated on 11/May/21

help me

helpme

Answered by TheSupreme last updated on 11/May/21

(1/x)+(1/y)+(1/z)=((xy+xz+yz)/(xyz))=(1/2)((2(xy+xz+yz)+x^2 +y^2 +z^2 −x^2 −y^2 −z^2 =)/(xyz)) =(1/2)(((x+y+z)^2 −(x^2 +y^2 +z^2 ))/(xyz))=(1/2)((7^2 −9)/5)=4

1x+1y+1z=xy+xz+yzxyz=122(xy+xz+yz)+x2+y2+z2−x2−y2−z2=xyz=12(x+y+z)2−(x2+y2+z2)xyz=1272−95=4

Answered by som(math1967) last updated on 11/May/21

(x+y+z)^2 =7^2 x^2 +y^2 +z^2 +2(xy+yz+zx)=49 (xy+yz+zx)=((49−9)/2) =20 ★ (1/x)+(1/y)+(1/z) =((yz+zx+xy)/(xyz))=((20)/5)=4 ans ∵x^2 +y^2 +z^2 =9

(x+y+z)2=72x2+y2+z2+2(xy+yz+zx)=49(xy+yz+zx)=49−92=20★1x+1y+1z=yz+zx+xyxyz=205=4ans∵x2+y2+z2=9

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