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Question Number 140688 by mohammad17 last updated on 11/May/21
Commented by mohammad17 last updated on 11/May/21
helpme
Answered by TheSupreme last updated on 11/May/21
1x+1y+1z=xy+xz+yzxyz=122(xy+xz+yz)+x2+y2+z2−x2−y2−z2=xyz=12(x+y+z)2−(x2+y2+z2)xyz=1272−95=4
Answered by som(math1967) last updated on 11/May/21
(x+y+z)2=72x2+y2+z2+2(xy+yz+zx)=49(xy+yz+zx)=49−92=20★1x+1y+1z=yz+zx+xyxyz=205=4ans∵x2+y2+z2=9
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