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Question Number 140698 by BHOOPENDRA last updated on 11/May/21

Commented by BHOOPENDRA last updated on 11/May/21

$B p a r t M r . W$
	Answered by mr W last updated on 11/May/21

	Commented by mr W last updated on 11/May/21

	$L = \frac{2 π r}{4} = \frac{π r}{2}$ $A = t d r$ $R = \frac{ρ L}{A} = \frac{ρ π r}{2 t d r}$ $d I = \frac{V}{R} = \frac{V 2 t d r}{ρ π r}$ $I = V \int \frac{2 t d r}{ρ π r}$ $R_{t o t a l} = \frac{V}{I} = \frac{1}{\int_{a}^{b} \frac{2 t d r}{ρ π r}} = \frac{ρ π}{2 t \int_{a}^{b} \frac{d r}{r}} = \frac{ρ π}{2 t \ln \frac{b}{a}}$
	Commented by BHOOPENDRA last updated on 11/May/21

	$t h a n k y o u$
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