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Question Number 140749 by SOMEDAVONG last updated on 12/May/21
∑nk=151k(1−5−1k(k+1))=?
Answered by Dwaipayan Shikari last updated on 12/May/21
51k(1−5−1k+1k+1)=51k−51k+1∑nk=1(51k−51k+1)=5−5+5−53+..+51n−51n+1=5−51n+1
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