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Question Number 140939 by iloveisrael last updated on 14/May/21

$$x^{\mathrm{sgn}(x^3-x)}=x^2-\frac{4}{9}$$

Answered by john_santu last updated on 14/May/21

$$x=-\frac{1}{3}\wedge x=\frac{4}{3}$$

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