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Question Number 141323 by mathocean1 last updated on 17/May/21

Answered by mr W last updated on 17/May/21

Commented by mr W last updated on 17/May/21

$$\cos \alpha =\frac{R-r}{R+r}$$$$BC=\frac{2R}{\tan \frac{\alpha }{2}}=2R\sqrt{\frac{1+\cos \alpha }{1-\cos \alpha }}=2R\sqrt{\frac{R}{r}}$$

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