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Question Number 141333 by cesarL last updated on 17/May/21

∫x^2 cos ((x/2))dx

$$\int{x}^{\mathrm{2}} \mathrm{cos}\:\left(\frac{{x}}{\mathrm{2}}\right){dx} \\ $$

Answered by qaz last updated on 17/May/21

∫x^2 cos (x/2)dx  =2x^2 sin (x/2)−4∫xsin (x/2)dx  =2x^2 sin(x/2) −4(−2xcos (x/2)+2∫cos (x/2)dx)  =2x^2 sin (x/2)+8xcos (x/2)−16sin (x/2)+C

$$\int{x}^{\mathrm{2}} \mathrm{cos}\:\frac{{x}}{\mathrm{2}}{dx} \\ $$$$=\mathrm{2}{x}^{\mathrm{2}} \mathrm{sin}\:\frac{{x}}{\mathrm{2}}−\mathrm{4}\int{x}\mathrm{sin}\:\frac{{x}}{\mathrm{2}}{dx} \\ $$$$=\mathrm{2}{x}^{\mathrm{2}} \mathrm{sin}\frac{{x}}{\mathrm{2}}\:−\mathrm{4}\left(−\mathrm{2}{x}\mathrm{cos}\:\frac{{x}}{\mathrm{2}}+\mathrm{2}\int\mathrm{cos}\:\frac{{x}}{\mathrm{2}}{dx}\right) \\ $$$$=\mathrm{2}{x}^{\mathrm{2}} \mathrm{sin}\:\frac{{x}}{\mathrm{2}}+\mathrm{8}{x}\mathrm{cos}\:\frac{{x}}{\mathrm{2}}−\mathrm{16sin}\:\frac{{x}}{\mathrm{2}}+{C} \\ $$

Commented by cesarL last updated on 17/May/21

Thank you bro

$${Thank}\:{you}\:{bro} \\ $$

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