All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 141367 by cesarL last updated on 18/May/21
∫(cosx⋅senx)dx
Answered by MJS_new last updated on 18/May/21
ifsenx=sinx∫cosxsinxdx=22∫sin2xdx=[t=x−π4→dx=dt]=22∫cos2tdt=22∫1−2sin2tdt==22E(t∣2)==22E(x−π4∣2)+C
Terms of Service
Privacy Policy
Contact: info@tinkutara.com