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Question Number 141423 by naka3546 last updated on 18/May/21
tan(x+y)=125sin(x−y)=35x+y,x−yareacuteangles.tanxtany=?
Answered by mr W last updated on 18/May/21
u=tanx,v=tanyu+v1−uv=125⇒u+v=12(1−uv)5tan(x−y)=34u−v1+uv=34⇒u−v=3(1+uv)4u=12(12(1−uv)5+3(1+uv)4)=63−33uv40u=12(12(1−uv)5−3(1+uv)4)=33−63uv40uv=63−33uv40×33−63uv402079(uv)2−6658(uv)+2079=0uv=3329±26002079=7727or2777
Commented by naka3546 last updated on 25/May/21
Thankyou,sir.
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