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Question Number 141534 by sarkor last updated on 20/May/21
Answered by som(math1967) last updated on 20/May/21
∫cos2xsin8xcosxdx=∫(1−sin2x)sin8xd(sinx)=∫sin8xd(sinx)−∫sin10xd(sinx)=19sin9x−111sin11x+C
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