((1/(1∙2∙3)))^2 +((1/(2∙3∙4)))^2 +((1/(3∙4∙5)))^2 +...=(1/(16))(4π^2 −39)


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Question Number 141577 by qaz last updated on 20/May/21

${(\frac{1}{1 \cdot 2 \cdot 3})}^{2} + {(\frac{1}{2 \cdot 3 \cdot 4})}^{2} + {(\frac{1}{3 \cdot 4 \cdot 5})}^{2} + . . . = \frac{1}{16} (4 π^{2} - 39)$
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