Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 141598 by Gbenga last updated on 20/May/21

Answered by TheSupreme last updated on 21/May/21

$$\frac{A}{x+3}+\frac{B}{x+2}=\frac{-2021}{(x+3)(x+2)}=\frac{Ax+2A+Bx+3B}{(x+3)(x+2)}$$$$A+B=0$$$$2A+3B=-2021$$$$A=2021$$$$B=-2021$$$$\mathrm{\Sigma }\frac{2021}{(x+3)}-\frac{2021}{(x+2)}$$$$telescopicseries$$$$\frac{2021}{6}-\frac{2021}{5}+\frac{2021}{7}-\frac{2021}{6}+\frac{2021}{8}-...$$$$\frac{2021}{(2018+3)}-\frac{2021}{5}=\frac{2021}{2021}-\frac{2021}{5}=1-404.2=-403.2$$

Commented by Gbenga last updated on 21/May/21

$$\mathit{T}hanks!!$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com