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Question Number 141599 by I want to learn more last updated on 20/May/21

$${\int }_1^3{\int }_{-1}^1{\int }_0^2(\mathrm{x}+2\mathrm{y}-\mathrm{z})\mathrm{dx}\mathrm{dy}\mathrm{dz}$$

Commented by I want to learn more last updated on 21/May/21

$$\mathrm{Thanks}\mathrm{sir}.$$

Answered by floor(10²Eta[1]) last updated on 21/May/21

$${\int }_1^3{\int }_{-1}^1{[\frac{{\mathrm{x}}^2}{2}+2\mathrm{yx}-\mathrm{zx}]}_0^2\mathrm{dydz}$$$${\int }_1^3{\int }_{-1}^1(2+4\mathrm{y}-2\mathrm{z})\mathrm{dyxz}$$$${\int }_1^3{[2\mathrm{y}+{2\mathrm{y}}^2-2\mathrm{zy}]}_{-1}^1\mathrm{dz}$$$${\int }_1^3(4-4\mathrm{z})\mathrm{dz}$$$${[4\mathrm{z}-{2\mathrm{z}}^2]}_1^3=-8$$

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