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Question Number 141651 by mathsuji last updated on 21/May/21

Commented by MJS_new last updated on 22/May/21

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{wrong}.$$$$a=b=c=0\Rightarrow 6\sqrt{2}>0$$$$a=b=c=-\sqrt{3}\Rightarrow 6\sqrt{2}>-6\sqrt{3}>-9\sqrt{3}$$

Commented by mathsuji last updated on 22/May/21

$$sorrysir,a,b,c>0$$

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