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Question Number 141654 by mathsuji last updated on 21/May/21

Solve for real numbers  5∙(((1−z))^(1/5)  + ((1+z))^(1/5)  = 2+4∙(((1−z))^(1/4)  + ((1+z))^(1/4) )

$${Solve}\:{for}\:{real}\:{numbers} \\ $$$$\mathrm{5}\centerdot\left(\sqrt[{\mathrm{5}}]{\mathrm{1}−{z}}\:+\:\sqrt[{\mathrm{5}}]{\mathrm{1}+{z}}\:=\:\mathrm{2}+\mathrm{4}\centerdot\left(\sqrt[{\mathrm{4}}]{\mathrm{1}−{z}}\:+\:\sqrt[{\mathrm{4}}]{\mathrm{1}+{z}}\right)\right. \\ $$

Commented by MJS_new last updated on 22/May/21

only solution is z=0

$$\mathrm{only}\:\mathrm{solution}\:\mathrm{is}\:{z}=\mathrm{0} \\ $$

Commented by mathsuji last updated on 22/May/21

solutions sir pliz

$${solutions}\:{sir}\:{pliz} \\ $$

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