_( −−−−−−−−−−−−−−−−−−−) x^2 (x−12)(x−15)=k(x−16) find x in terms of k (>0). ^(−−−−−−−−−−−−−−−−−−−)


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Question Number 141663 by ajfour last updated on 22/May/21

$\underset{- - - - - - - - - - - - - - - - - - -}{}$ $x^{2} (x - 12) (x - 15) = k (x - 16)$ $f i n d x i n t e r m s o f k (> 0) .$ $\overset{- - - - - - - - - - - - - - - - - - -}{}$
Commented byRasheed.Sindhi last updated on 22/May/21

$\frac{x^{2} (x - 12) (x - 15)}{x - 16} = k$ $k > 0 \Rightarrow x ≰ 12 \land 15 ≰ x ≰ 16$ $\Rightarrow x \in (12, 15) \cup (16, \infty)$
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