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Question Number 141669 by bramlexs22 last updated on 22/May/21
Answered by iloveisrael last updated on 22/May/21
(i)f(a)=g(a),a>0⇒a+∣2a∣=−a2−23a+143⇒3a=−a2−23a+143⇒3a2+9a+2a−14=0⇒3a2+11a−14=0(ii)f(c)=g(c);c<0⇒−c=−c2−23c+143⇒3c2−3c+2c−14=0⇒3c2−c−14=0
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