Daniel and Bruno are playing with perfect cube Daniel is the first player if he obtains 1 or 2 he wins the game and the party stopping or else Bruno plays and if he have {3.4.6} Bruno won and the game stopping Determine the probability that Daniel winand the probability that Bruno win


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Question Number 141692 by ArielVyny last updated on 22/May/21

$D a n i e l a n d B r u n o a r e p l a y i n g w i t h p e r f e c t c u b e$ $D a n i e l i s t h e f i r s t p l a y e r i f h e o b t a i n s 1 o r 2$ $h e w i n s t h e g a m e a n d t h e p a r t y s t o p p i n g$ $o r e l s e B r u n o p l a y s a n d i f h e h a v e {3.4.6} B r u n o w o n a n d t h e g a m e s t o p p i n g$ $D e t e r m i n e t h e p r o b a b i l i t y t h a t D a n i e l w i n a n d t h e p r o b a b i l i t y t h a t B r u n o w i n$
	Answered by MJS_new last updated on 22/May/21

	$in \frac{1}{3} of all cases Daniel wins$ $in \frac{2}{3} of all cases Bruno plays$ $in \frac{3}{6} = \frac{1}{2} of these cases Bruno wins$ $the rest end in a draw$ $\Rightarrow$ $Daniel wins \frac{1}{3}$ $Bruno wins \frac{2}{3} \times \frac{1}{2} = \frac{1}{3}$ $draw \frac{1}{3}$
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