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Question Number 141699 by cesarL last updated on 22/May/21
Iflimx→1=xk−1x−1=L≠0Findlimx→0x+1−1x+1k−1
Answered by iloveisrael last updated on 22/May/21
Givenlimx→1xk−1x−1=Lequivalenttolimt→1t−1tk−1=L⇔limx→0x+1−1x+1k−1letx+1=t2k;x→0∧t→1limt→1tk−1t2−1=1limt→1(t−1tk−1).limt→1(t+1)=12L
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