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Question Number 142017 by cherokeesay last updated on 25/May/21

Commented by cherokeesay last updated on 25/May/21

  1) Calculate R   2) Calculate the% of the area of ​​the hatched part compared to the area of ​​the half disk of Radius R.

$$ \\ $$1) Calculate R 2) Calculate the% of the area of ​​the hatched part compared to the area of ​​the half disk of Radius R.

Commented by mr W last updated on 26/May/21

better solve this:

$${better}\:{solve}\:{this}: \\ $$

Commented by mr W last updated on 26/May/21

Answered by help last updated on 26/May/21

2+(√3)

$$\mathrm{2}+\sqrt{\mathrm{3}} \\ $$

Answered by help last updated on 26/May/21

Commented by cherokeesay last updated on 26/May/21

thank you sir !  very nice.

$${thank}\:{you}\:{sir}\:! \\ $$$${very}\:{nice}. \\ $$

Answered by mr W last updated on 26/May/21

((3/r)−(1/R))^2 =2((3/r^2 )+(1/R^2 ))  ((3R^2 )/r^2 )−((6R)/r)−1=0  ⇒(R/r)=((3+2(√3))/3)  ⇒R=(1+(2/( (√3))))(√3)=2+(√3)

$$\left(\frac{\mathrm{3}}{{r}}−\frac{\mathrm{1}}{{R}}\right)^{\mathrm{2}} =\mathrm{2}\left(\frac{\mathrm{3}}{{r}^{\mathrm{2}} }+\frac{\mathrm{1}}{{R}^{\mathrm{2}} }\right) \\ $$$$\frac{\mathrm{3}{R}^{\mathrm{2}} }{{r}^{\mathrm{2}} }−\frac{\mathrm{6}{R}}{{r}}−\mathrm{1}=\mathrm{0} \\ $$$$\Rightarrow\frac{{R}}{{r}}=\frac{\mathrm{3}+\mathrm{2}\sqrt{\mathrm{3}}}{\mathrm{3}} \\ $$$$\Rightarrow{R}=\left(\mathrm{1}+\frac{\mathrm{2}}{\:\sqrt{\mathrm{3}}}\right)\sqrt{\mathrm{3}}=\mathrm{2}+\sqrt{\mathrm{3}} \\ $$

Commented by cherokeesay last updated on 26/May/21

thank you mister W.

$${thank}\:{you}\:{mister}\:{W}. \\ $$$$ \\ $$

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