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Question Number 142021 by mathmax by abdo last updated on 25/May/21

$$\mathrm{simplfy}\mathrm{f}\left(\mathrm{x}\right)=\tan \left(\alpha \mathrm{arcsinx}\right)$$$$\mathrm{and}\mathrm{g}\left(\mathrm{x}\right)=\tan \left(\alpha \mathrm{arcosx}\right)\alpha \mathrm{is}\mathrm{real}$$$$\mathrm{x}\in [-1,1]$$

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