[lim_(x→0) ((sin x)/x)]=? lim_(x→0) {[((100sin^(−1) x)/x)]+[((100tan^(−1) x)/x)]}=? lim_(x→0) {[((100x)/(sin^(−1) x))]+[((100x)/(tan^(−1) x))]}=? where [x] denotes greatest integer less than or equal to x. solution please


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Question Number 142140 by gsk2684 last updated on 26/May/21
$[lim_(x→0) ((sin x)/x)]=? lim_(x→0) {[((100sin^(−1) x)/x)]+[((100tan^(−1) x)/x)]}=? lim_(x→0) {[((100x)/(sin^(−1) x))]+[((100x)/(tan^(−1) x))]}=? where [x] denotes greatest integer less than or equal to x. solution please$
$[\lim_{x \to 0} \frac{\sin x}{x}] = ?$ $\lim_{x \to 0} {[\frac{{100 \sin}^{- 1} x}{x}] + [\frac{{100 \tan}^{- 1} x}{x}]} = ?$ $\lim_{x \to 0} {[\frac{100 x}{\sin^{- 1} x}] + [\frac{100 x}{\tan^{- 1} x}]} = ?$ $w h e r e [x] d e n o t e s g r e a t e s t i n t e g e r$ $l e s s t h a n o r e q u a l t o x .$ $s o l u t i o n p l e a s e$
	Answered by mathmax by abdo last updated on 27/May/21

	$\lim_{x \to 0} \frac{sinx}{x} = 1 \Rightarrow [\lim_{x \to 0} \frac{sinx}{x}] = 1$
	Commented by gsk2684 last updated on 27/May/21

	$thank you$
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