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Question Number 142148 by islamo last updated on 27/May/21

$$\underset{n=0}{\sum ^{\mathrm{\infty }}}\frac{1}{n!}=?$$

Answered by mathmax by abdo last updated on 27/May/21

$${\mathrm{e}}^{\mathrm{x}}=\sum _{\mathrm{n}=0}^{\mathrm{\infty }}\frac{{\mathrm{x}}^{\mathrm{n}}}{\mathrm{n}!}\Rightarrow \mathrm{e}=\sum _{\mathrm{n}=0}^{\mathrm{\infty }}\frac{1}{\mathrm{n}!}$$

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