Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 142205 by mohammad17 last updated on 27/May/21

Commented by mohammad17 last updated on 27/May/21

$$helpmesir?$$

Commented by mohammad17 last updated on 27/May/21

$$yessircanyouhelpme?$$

Commented by mr W last updated on 27/May/21

$$hehashelpedyou!$$$$whatyoustillwantisnotcalledhelp.$$

Commented by liberty last updated on 28/May/21

$$\left(1\right)y=\frac{2}{3}{x}^{\frac{3}{2}}\Rightarrow y^{\prime }=\sqrt{x}$$$$arclength=\underset{1}{\stackrel{2}{\int }}\sqrt{1+{\left(\sqrt{x}\right)}^2}dx$$$$=\underset{1}{\stackrel{2}{\int }}\sqrt{1+x}d(1+x)=\frac{2}{3}{\left[\sqrt{{(1+x)}^3}\right]}_1^2$$$$=\frac{2}{3}(\sqrt{27}-\sqrt{8})=\frac{2}{3}(3\sqrt{3}-2\sqrt{2})$$

Commented by MJS_new last updated on 27/May/21

$$\mathrm{arc}\mathrm{length}\mathrm{of}f\left(t\right)\mathrm{for}a⩽t⩽b\mathrm{is}\underset{a}{\stackrel{b}{\int }}\sqrt{1+{\left(f{}^{\prime }\left(t\right)\right)}^2}dt$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com