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Question Number 142252 by Algoritm last updated on 28/May/21

Answered by MJS_new last updated on 29/May/21

solve the 2^(nd)  for x then insert into the 1^(st)   let y=2arctan t  solve for t  check all solutions  ⇒  x≈1.25974557∧y≈−1.413005690  ∨  x≈−.920053464∧y≈−2.57242041  exact solutions possible but too complex to  handle  you can do the details following my “recipe”

$$\mathrm{solve}\:\mathrm{the}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{for}\:{x}\:\mathrm{then}\:\mathrm{insert}\:\mathrm{into}\:\mathrm{the}\:\mathrm{1}^{\mathrm{st}} \\ $$$$\mathrm{let}\:{y}=\mathrm{2arctan}\:{t} \\ $$$$\mathrm{solve}\:\mathrm{for}\:{t} \\ $$$$\mathrm{check}\:\mathrm{all}\:\mathrm{solutions} \\ $$$$\Rightarrow \\ $$$${x}\approx\mathrm{1}.\mathrm{25974557}\wedge{y}\approx−\mathrm{1}.\mathrm{413005690} \\ $$$$\vee \\ $$$${x}\approx−.\mathrm{920053464}\wedge{y}\approx−\mathrm{2}.\mathrm{57242041} \\ $$$$\mathrm{exact}\:\mathrm{solutions}\:\mathrm{possible}\:\mathrm{but}\:\mathrm{too}\:\mathrm{complex}\:\mathrm{to} \\ $$$$\mathrm{handle} \\ $$$$\mathrm{you}\:\mathrm{can}\:\mathrm{do}\:\mathrm{the}\:\mathrm{details}\:\mathrm{following}\:\mathrm{my}\:``\mathrm{recipe}'' \\ $$

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