Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 14246 by tawa tawa last updated on 30/May/17

Commented by ajfour last updated on 30/May/17

Commented by ajfour last updated on 30/May/17

a=((v−u)/(Δt)) =((25−30)/3)=−(5/3)m/s^2   let total time to stop be T, then  from v=u+at  0=30−(5/3)T    ⇒ T=18s  and from:  s=ut+(1/2)at^2    distance=30×18−((1/2))((5/3))(18)^2                      =540−270                      =270m .

$${a}=\frac{{v}−{u}}{\Delta{t}}\:=\frac{\mathrm{25}−\mathrm{30}}{\mathrm{3}}=−\frac{\mathrm{5}}{\mathrm{3}}{m}/{s}^{\mathrm{2}} \\ $$$${let}\:{total}\:{time}\:{to}\:{stop}\:{be}\:{T},\:{then} \\ $$$${from}\:\boldsymbol{{v}}=\boldsymbol{{u}}+\boldsymbol{{at}} \\ $$$$\mathrm{0}=\mathrm{30}−\frac{\mathrm{5}}{\mathrm{3}}{T}\:\:\:\:\Rightarrow\:{T}=\mathrm{18}{s} \\ $$$${and}\:{from}:\:\:\boldsymbol{{s}}=\boldsymbol{{ut}}+\frac{\mathrm{1}}{\mathrm{2}}\boldsymbol{{at}}^{\mathrm{2}} \\ $$$$\:{distance}=\mathrm{30}×\mathrm{18}−\left(\frac{\mathrm{1}}{\mathrm{2}}\right)\left(\frac{\mathrm{5}}{\mathrm{3}}\right)\left(\mathrm{18}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{540}−\mathrm{270}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{270}{m}\:. \\ $$

Commented by tawa tawa last updated on 30/May/17

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Answered by ajfour last updated on 30/May/17

Commented by ajfour last updated on 30/May/17

(2A)^2 +A^2 =64  5A^2 =64  A=(8/(√5))  .

$$\left(\mathrm{2}{A}\right)^{\mathrm{2}} +{A}^{\mathrm{2}} =\mathrm{64} \\ $$$$\mathrm{5}{A}^{\mathrm{2}} =\mathrm{64} \\ $$$${A}=\frac{\mathrm{8}}{\sqrt{\mathrm{5}}}\:\:. \\ $$

Commented by tawa tawa last updated on 30/May/17

Thanks for everytime. God bless you sir.

$$\mathrm{Thanks}\:\mathrm{for}\:\mathrm{everytime}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com