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Question Number 142604 by Engr_Jidda last updated on 02/Jun/21

Answered by mr W last updated on 02/Jun/21

$$a=14$$$$r_1=b=10.5$$$$r_2=\sqrt{a^2+b^2}-b$$$$r_3=b-r_2=2b-\sqrt{a^2+b^2}$$$$\alpha ={\tan }^{-1}\frac{b}{a}$$$$S=\frac{ab}{2}-\frac{r_1^2\alpha }{2}-\frac{r_2^2(\frac{\pi }{2}-\alpha )}{2}-\frac{\pi r_3^2}{4}$$

Commented by Engr_Jidda last updated on 03/Jun/21

$$thankyousir$$

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