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Question Number 142630 by iloveisrael last updated on 03/Jun/21

$$Givenf\left(x\right)=\frac{1}{1+2^x}$$$$findthevalueof$$$$f\left(\frac{1}{2018}\right)\times f\left(\frac{3}{2018}\right)\times f\left(\frac{2015}{2018}\right)\times f\left(\frac{2017}{2018}\right)=?$$

Commented by MJS_new last updated on 03/Jun/21

$$\mathrm{no}‘‘{\mathrm{nice}}^{″}\mathrm{value}$$$$a=\frac{1}{2018}$$$$f\left(a\right)f\left(3a\right)f(1-3a)f(1-a)=$$$$=\frac{{16}^a}{(2^a+1)(2^a+2)(8^a+1)(8^a+2)}\approx .0277841315$$

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