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Question Number 142802 by Gbenga last updated on 05/Jun/21

$$x=2w\left(e^{-1}\right)$$

Commented by Dwaipayan Shikari last updated on 06/Jun/21

$$W\left(x\right)=\underset{n=1}{\sum ^{\mathrm{\infty }}}\frac{{(-n)}^{n-1}}{n!}{x}^n$$$$x=\frac{2}{e}-2{\left(\frac{1}{e}\right)}^2+3{\left(\frac{1}{e}\right)}^3-..$$

Answered by MJS_new last updated on 06/Jun/21

$$\mathrm{if}w\left(x\right)\mathrm{is}\mathrm{the}\mathrm{Lambert}-\mathrm{W}-\mathrm{function}$$$$x\approx .556929085522$$

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